Arectangular two-story horse barn is being designed for a farm. the upper floor will be used for storing hay, and the lower floor will have horse stalls that extend 6 feet from both of the longer walls. the barn's length is twice the barn's width, and the lower floor's ceiling height is 8 feet less than the barn's width. what should the dimensions of the lower floor be if the space not used for stalls is to have a volume of 3,840 cubic feet?

Let the width of the barn be = x feet

So length of the barn = 2x

Height of the barn = x-8

As the stalls are 6 feet longer from both ends hence, we have to find the area with width as x-12 feet

Volume of the space is = 3840 cubic feet

Hence, equation is :

Solving this we get

This gives x=20 and x= ±

Hence, neglecting the square root value we get x = 20 feet

Hence, the width is = x-12 = 20 - 12 = 8 feet

Length is = 2x = 2*20 = 40 feet

Height is = x-8 = 20 - 8 =12 feet

And we can cross check this by multiplying all the three dimensions to get 3840 cubic feet

cubic feet.

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step-by-step explanation:

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)