Ajuggler tosses a ball into the air . the balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40t+4 . suppose the juggler missed and ball hit the ground . find the maximum height of the ball and time it took to reach the ground. round all answers to the nearest hundredth .

Maximum height is 29 ft

Time to reach the ground is 2.60 seconds

Step-by-step explanation:

We are given equation of height as

Maximum height:

we know that at maximum height

velocity =0

so, we will find derivative

and then we can set it to 0

and we solve for t

now, we can set it to 0

and then we can solve for t

now, we can plug t into height equation

Time to reach the ground:

we know that at ground

height=0

so, we can set h(t)=0

and then we can solve for t

we can use quadratic formula

Since, time can never be negative

so, we will only consider positive time

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.