Write an equation of the line that passes through the given point and is parallel to the given line: (-3,-7); y=-3x+4 (4,6); 4x+2y=10 explain how to do this! i'm really bad at the passing points of perpendicular and parallel lines!

(1)

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - 3x + 4 is in this form with slope m = - 3

• Parallel lines have equal slopes, thus

y = - 3x + c ← is the partial equation

To find c substitute (- 3, - 7 ) into the partial equation

- 7 = 9 + c ⇒ c = - 7 - 9 = - 16

y = - 3x - 16 ← equation of line

(2)

rearrange 4x + 2y = 10 into slope- intercept form

subtract 4x from both sides

2y = - 4x + 10 ( divide all terms by 2 )

y = - 2x + 5 ← in slope- intercept form with m = - 2

y = - 2x + c ← partial equation

to find c substitute (4, 6 ) into the partial equation

6 = - 8 + c ⇒ c = 6 + 8 = 14

y = - 2x + 14 ← equation of line

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