Asquare has a side length x cm and area a cm2. the area is increasing at a constant rate of 0.03 cm2s-1.find the rate of increase of x when a=25. ( solve and explain? )

The rate of increase of x when A = 25 is 0.0006 cm/s.

Step-by-step explanation:

Area of a square A = sq. cm

So, x = cm

--- (1)

It is given that the area is increasing at the rate of 0.03 /s.

Therefore,

We need to find the rate of increase of x when A = 25.

Now, substituting the values of A and , (1) becomes

= 0.0006

Hence, the rate of increase of x when A = 25 is 0.0006 cm/s.