Find the i)nth term, ii)the 10th term, iii)the 50th term of each of these sequences. a)3,5,7,9, b)5,9,13,17, c)8,13,18,23, d)2,8,14,20, e)5,8,11,14, f)2,9,16,23, g)1,5,9,13, h)3,7,11,15, i)2,5,8,11, j)2,12,22,32, k)8,12,16,20, l)4,9,14,19,

I'll help you solve the first one, the rest are up to you, but they all use basically the same idea.

Ok so for A, we will call each position "n". So the first position (n=1) is equal to 3, which is n*2+1. The second position (n=2) is equal to 5, use the same equation n*2+1, however this time n is equal to two so the equation is 2*2+1=5. Now for the third position (n=3), again n*2+1, substitute 3 for n and we get 3*2+1=7.

So the statement is find the 10th term, you know the formula (n*2+1) so just plug 10 in for n. Do this for 50 also.

If you need more help leave a comment.

2xy/9 is the answer to this problem