Coach mac finds a new practice court for the basketball team. if the width of the rectangular lot is 16 feet less than the length. the perimeter is 160 feet, what are the dimensions of the new practice court? perimeter of rectangle is = 2w + 2l 160=2w+2l; w=

System of equations

Solution to system of equations

The width is 16 feet less than the length, so the appropriate equation for that is ...

... W = L - 16

Using this expression for W, we can substitute into the equation for perimeter:

... 160 = 2(L - 16) + 2L

... 160 = 4L -32 . . . . . . . collect terms

... 192 = 4L . . . . . . . . . . add 32

... 48 = L . . . . . . . . . . . . divide by 4

... W = 48 -16 = 32 . . . . find W using the relation with L

Length is 48 ft; width is 32 ft.

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt