Write an equation of the line that passes through the given points. (-1,4) and (3,0)

As we go from (-1,4) to (3,0), increases by 4 and y decreases by 4.  Thus, the slope of this line is m = rise / run = -4/4 = -1.

Let's use the slope-intercept form of the equation of a line:

y = mx + b

Replace y with 0 and x with 3 (from (3,0), and m with -1:

0 = (-1)(3) + b.  Then b = 3, and the desired equation is y = -x + 3.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)