Aball is dropped from a height of 10 meters. each time it bounces, it reaches 50 percent of its previous height. the total vertical distance down the ball has traveled when it hits the ground the fifth time is?

0.3125

Step-by-step explanation:

When The ball bounces the first time it goes 5 meters up. In The second bounce it goes 2.5 Meters. And Then In The 3rd bounce it goes up 1.25 Meters. And Then in the forth Bounce it goes up 0.625 Meters. And In The FINAL Bounce It Goes up 0.3125 Meters = to 31.25 Cm - just extra information

Formula For This is

To Divide 10 by Two 5 Times

10   ÷ 2 = 5

5  ÷ 2 = 2.5

2.5  ÷ 2 = 1.25

1.25  ÷ 2 = 0.625

0.625  ÷ 2 = 0.3125

Your Welcome

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step-by-step explanation:

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4