Can someone me ! let n be the least postive integer whose digits sum to 2018. compute the sum of the digits of n+1.

3

Explanation:

Since we want the least number of integers, divide by the largest integer (9).

2018 ÷ 9 = 224 remainder 2

So, N = 2999...999 (there are 224 of the 9's)

Thus, N + 1 = 2999...999 + 1 (there are 224 of the 9's)

                  = 3000...000     (there are 224 of the 0's)

The sum of the digits is: 3 + 0 + ... + 0  (there are 224 of the 0's)

                                      = 3

i think the answer is b.

step-by-step explanation:

not 100% sure though.

costs the what? what is the cost of the pants?

step-by-step explanation:

if it is $10, then the price is 14.

take 40% of the cost, and then add the cost.

40% of 10 = 4

4+10 = 14.