Given the function f(x)=(x+1)^2.what is the value of f(-2)

1

Explanation:

f(x) = (x + 1)²

f(-2) is found by replacing "x" with "-2"

f(-2) = (-2 + 1)²

       = (-1)²

       = 1

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.