To rent a certain meeting room, a college charges a reservation fee of $35 and an additional fee of $9.90 per hour. the chemistry club wants to spend at most $94.40 on renting the meeting room. what are the possible amounts of time for which they could rent the meeting room? use t for the number of hours the meeting room is rented, and solve your inequality for t.

To rent a certain meeting room, a college charges a reservation fee of $35 and an additional fee of $9.90 per hour.

Let t be the number of hours rented

charge for renting a meeting room is 9.90t +35

The chemistry club wants to spend at most $94.40 on renting the meeting room.

so charge is less than or equal to 94.40

The inequality becomes 9.90t + 35 <=94.40

Solve the inequality for t

9.90t + 35 <=94.40

Subtract both sides by 35

9.90t < = 59.4

Divide both sides by 9.90

t < = 6

So, they could rent the meeting room for maximum of 6 hours.

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24