To rent a certain meeting room, a college charges a reservation fee of $42 and an additional fee of $7.60 per hour. the math club wants to spend less than $110.40 on renting the meeting room. what are the possible amounts of time for which they could rent the meeting room? use t for the number of hours the meeting room is rented, and solve your inequality for t.

T = hours

42+ 7.6T < 110.40

subtract 42 from each side

7.6T < 110.40 -42

7.6T < 68.4

divide each side by 7.6

T < 9

T >= 0 as well because you cannot rent less than 0 hours

0<= T < 9 hours

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6