Which is the graph of the following equation?

Given equation is

The given equation is in the form of

a^2= 16  , so a=4

b^2 = 9 so b= 4

The value of 'a' is greater than the value of 'b'

So it is a Horizontal hyperbola

First two graphs are horizontal hyperbola

Here center is (h,k)  

h= 5 and k =2 from the given equation

So center is (5,2)

Now we find vertices

Vertices are (h+a,k)  and (h-a,k)

We know h=5, k=2  and a=4

So vertices are (9,2)  and (1,2)

Second graph having same vertices and center

The correct graph is attached below

step-by-step explanation:

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}