I'm stuck line q is a vertical translation of line s 3 units down. p'' is the image of p' . what are the coordinates of p'' ?

The coordinates of P" is (m,n+e-3).

Step-by-step explanation:

From the figure it is noticed that the line s is vertical transformation of line r, e units up. Then the x coordinates are same as in line r, but e units subtracted from y-coordinates.

If a graph vertically translated by m units up, then

If a graph vertically translated by m units down, then

Since the line Q is a vertical translation of line S, 3 units down, therefore x-coordinate remains same but 3 units are subtracted from y-coordinate.

It is given that P" is the image of P' and P'(m,n+e).

Therefore the coordinates of P" is (m,n+e-3).

21.4 i did it already for s1

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v