Idraw a card from a poker deck, and without replacing it, draw another. what is the probability i get two aces

For the first card drawn it is 4/52 or 1/13 it is an ace

When drawing the second card the odds are 3/51 or 1/17 it is an ace

The odds that BOTH cards are aces = 1/13 * 1/17 = 1/221

Step-by-step explanation:

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: