If you flip three fair coins, what is the probability that you'll get two tails and one head in any order?

Since the order of the outcomes don’t matter we also have to figure out how many different sequences exist.

Head, tail, tail

Tail, head, tail

Tail, tail, head

So we have 3 unique orders for the coins. Putting these two things together we get 3 times 1/8 =3/8 and this then answers your question.

3/8

Step-by-step explanation:

answer: h=5.6 i don't really know how to put into words, so i though i would let you do that. i hope i was able to some

step-by-step explanation:

18 = 6(h)+1/2

18 = 6h+1/2

18-1 = 6h/2

17 = 3h

17/3 = h

h = 5.6