Write an equation for the perpendicular line to the line whose equation is 4y-5x=20 that contains the point (-2,-3)

The equation of a parallel line in point-slope form would be y = -4/5x - 23/5

Step-by-step explanation:

To find this, we must first find the slope of the original line. We can do this by solving for y.

4y - 5x = 20

4y = 5x + 20

y = 5/4x + 5

Now that we have the slope of the original line, we can find the slope of the new line. Perpendicular lines have opposite and reciprocal slopes, which means that while the original slope was 5/4, the new one will be -4/5. Now that we have that, we can use the point and slope and put them into the base form of point-slope form. Then we solve for y to get the final result.

y - y1 = m(x - x1)

y + 3 = -4/5(x + 2)

y + 3 = -4/5x - 8/5

y = -4/5x - 23/5

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet