8. part a: find the value of x. a. x=2 b. x=3 c. x=4 d. x=6 8. part b: in the previous question, what is the distance from a side of the triangle to the incenter? a. 23 units b. 15 units c. 11 units d. 7 units if someone could me, i would very much appreciate

x =2

7 units

Step-by-step explanation:

As we can see, OD = OE

<=> 4x -1  = 6x -5  

<=> 2x  =4

<=> x=2

Substitute x = 2 into OD we have:

4*2 -1 = 7 units

or Substitute x = 2 into OE we have:

6*2 -5 = 7 units

So the distance from a side of the triangle to the incenter is 7 units

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629