Write the following equation in logarithmic form a^(4b-6)=3c+d

Hello from MrBillDoesMath!

 (4b-6) log(a) = log (3c + d)

Discussion:

Take the log of both sides of the equation:

log ( a ^(4b-6))  = log (3c + d)  

As the log functions causes exponents to become multiplexers, this equation is the same as

(4b-6) log(a) = log (3c + d)

Thank you,

MrB

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

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step-by-step explanation: