Use an arithmetic sequence to find the number of multiples of 6 between 41 and 523. justify your reasoning.

The number of multiples of 6 between 41 and 523 = 81

Step-by-step explanation:

We need to find multiples of 6 between 41 and 523.

First multiple is 42.

That is first term is 42.

Common difference is 6.

The last term less than 523 and multiple of 6 is 522.

So we need to find number of terms in

               42, 48, 54 , 60 , 66 522

           We have

                       a + (n-1) d = 522

                      42 + (n-1) 6 = 522

                       (n-1) 6 = 522 - 42 = 480

                          (n-1) = 80

                            n = 81

That is there are 81 terms in this arithmetic progression.

The number of multiples of 6 between 41 and 523 = 81

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

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