(a^4(3a^2b)^3)/((3ab^2)^-1) exponent has to be postive and has to be simplified

81a^8b^12

Step-by-step explanation:

When you have an exponent to an exponent multiply the exponents.

(3a^2b^3)^4

=81a^8b^12

Ed

To do this problem, you need to raise each of the individual terms inside the parentheses

to the 4th power.

In other words:

Now you can recognize that 3%5E4 is 3*3*3*3 and this product is 81. So you can substitute

81 in place of 3%5E4 and the problem is reduced to:

.

81%2A%28a%5E2%29%5E4%2A+%28b%5E3%29%5E4

.

Next look at %28a%5E2%29%5E4. You can get an equivalent form of this by multiplying the exponent

4 by the exponent 2 to get a%5E8. You can also think of %28a%5E2%29%5E4 as being a%5E2

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.