Which postulate can be used to prove that abd and cbd are congruent given that bd and ac and bd bisects ac sas sss asa ssa

SAS

Step-by-step explanation:

Here we are given two situations:

BD⊥AC

This indicates that angle ADB and CDB are 90 degrees.

Aso we are given that BD bisects AC.

This indicates that AD=DC

So in triangles ADB and CDB , we have

BD=BD (common) (Side)

angle ADB= angle CDB (Angle)

AD=DC (side)

So the two triangles are congruent by SAS congruency.

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: