Which equation represents a parabola that opens upward has a minimum at x=3 and has a line of symmetry at x=3

Step-by-step explanation:

Let us consider the equation

For a quadratic equation in a standard form, , the axis of symmetry is the vertical line .

Here in this case we have,

Putting the values we get,

We can see that the axis of symmetry is x=3 and the graph is giving minimum at x=3.

Therefore, the required equation is . Refer the image attached.

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1