How much would 300 invested at 9 interest compounded continuously be worth after 3years

392.99

Step-by-step explanation: Starting Principal: 300

Interest Rate: 9

Years: 3

Then solve

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.