Two lines have the following equations 4x+3y=7 x+2y=-2 at what point do they intersect a.(1,1)b.(0,-1)c.(4,-3)d.(6,-4) !

(4,-3)

Step-by-step explanation:

Easiest way to do this without any advanced methods is to use the answer choices to your advantage.  

For a.) we have (1,1) meaning x = 1 and y = 1 if we get a 7 for the first equation and a -2 for the second equation then that is the correct answer.

Let x=1, y =1:

4(1)+3(1)=4+3=7  Correct so far.

1+2(1)=1+2=3      Incorrect since we should have got a -2 if this was the solution

Let (0,-1) x = 0, y = -1:

4(0) + 3(-1) = 0 -3 = - 3 Incorrect so we can stop there next answer choice.

Let (4,-3) x = 4 y = -3:

4(4)+3(-3)=16-9=7   Correct so far.

4+2(-3)=4-6=-2      Both are correct!

Therefore the solution (where the lines intersect) is (4,-3).

i think it's either c or d

step-by-step explanation: the entire question is extremely odd. 04 obviously refers to the interest rate. honestly i will say the answer is c. because the (2 x 12) part would mean it's compounded semiannually. i'll say choose c.