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Mathematics, 30.06.2019 00:30 andrwisawesome0

Solve by substitution. choose all that apply. 2x + y = 5 3x - 3y = 3 select one or more: a. the solution has a negative y value. b. the solution has both a negative x and a negative y. c. the solution has a negative x value. d. the solution has a positive x value. e. no solution solve by substitution. 2x - y = 7 6x - 3y = 14 select one: a. no solution b. the solution has a negative x value. c. infinitely many solutions d. the solution has a positive x value. solve by elimination. 2x - y = 7 3x + y = 8 select one: a. the solution has two positive values. b. the solution has a negative x value. c. the solution has one positive and one negative value. d. the solution has a positive y value. solve by elimination. 3x - y = 12 5x + 2y = 20 select one: a. the solution has one value that is zero. b. the solution has two positive values. c. the solution has one positive and one negative value. d. the solution has two negative values. solve by any method you choose. 3x + y = 8 3x + 3/2 y = 12 select one: a. there are no solutions to the system. b. there is one solution to the system. c. there are infinitely many solutions to the system.

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Solve by substitution. choose all that apply. 2x + y = 5 3x - 3y = 3 select one or more: a. the sol...
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