Divide (2x^2+10x+7) divided by (x+2) i need the quotient and remainder asap

Hello!

When we are dividing polynomials, we need to find their common factors.

Looking at the first term in  the dividend with the divisor, it's common factor is 2x.

We would multiply 2x by the binomial (x + 2) and subtract it.

2x(x + 2) = 2x² + 4x

2x² + 10x + 7 - (2x² + 4x)

2x² + 10x + 7 - 2x² - 4x = 6x + 7

We are left with 6x + 7. Now, we need to find the common factor in 6x, which is 6, and multiply 6 by the divisor and subtract.

6(x + 2) = 6x + 12

6x + 7 - (6x + 12)

6x + 7 - 6x - 12 = -5

Therefore, the quotient is 2x + 6, with a remainder of -5.  

113.1

step-by-step explanation:

v=4

3πr3=4

3·π·33≈113.09734

alright so i think for this one it would to draw it out. this may be hard for me to try and draw, but i will do my best on here:

        r

  /       |     \

notice how it forms 2 triangles inside one bigger triangle.

so if we know the angle spr is the same as psr that is saying the measure of angle p is the same as angle s. this means the big triangle psr is either isosceles or equilateral. in both cases, the triangle is perfectly symmetrical when split down the middle, which is in this case rq. because we know it is perfectly symmetrical on both sides, we know that the two triangles inside the bigger one are equal.