Mr. rich had 2 times more cars than motorcycles in his garage. after he bought 1 more car and sold 2 motorcycles, there were 3 times more cars than motorcycles. how many cars and motorcycles were there in garage?

Hence no of cars (C) is 14, and no of bikes, M is 7.

Step-by-step explanation:

Let the no of cars be C and number of motorcycles be M.

First statement mentions that no of cars (c) is twice no of motorbikes, hence

C=2M

Second statement says, when no of cars is increased by 1, and motorcycles is reduced by 2, the calculations change as-

C+1 = 3(M-2)

On solving the two, we have

C=2M

C+1=3(M-2)

Solving eq 2

C+1=3M-6 (Subtracting 1 from both sides)

C=3M-7

Putting eq 1 & 2 together-

3M-7=2M (sub 2m from both sides)

M-7=0

M=7

Now M is 7. Put it in eq 1

C=2M

C=2(7)

C=14

Hence no of cars (C) is 14, and no of bikes, M is 7.

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

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