Ajet can fly at a rate of 480 mi/h in calm air. traveling with the wind, the plane flew 1560 mi in the same amount of time it took to fly 1320 mi against the wind. find the rate of the wind.

Let the Rate of the Wind be : W mi/h

Given : The Jet can fly at a rate of 480 mi/h

⇒ Travelling with the Wind, Jet flies with a speed of (480 + W) mi/h

⇒ Travelling against the Wind, Jet flies with a speed of (480 - W) mi/h

Given : The Jet Travels 1560 Miles, Travelling with the Wind

Let us calculate How much time the Jet takes to Travel 1560 Miles

In One Hour : The Jet travels a Distance of (480 + W) Miles

⇒ The Jet travels a Distance of 1560 Miles in :

Given : The Jet Travels 1320 Miles, Travelling against the Wind

Let us calculate How much time the Jet takes to Travel 1320 Miles

In One Hour : The Jet travels a Distance of (480 - W) Miles

⇒ The Jet travels a Distance of 1320 Miles in :

Given : Time taken to fly 1560 Miles with the Wind = Time taken to fly 1320 Miles against the Wind.

⇒

⇒ 1560(480 - W) = 1320(480 + W)

⇒ (1560 × 480) - 1560W = (1320 × 480) + 1320W

⇒ 1560W + 1320W = (1560 × 480) - (1320 × 480)

⇒ 2880W = 480(240)

⇒ 288W = 48(240)

⇒ 72W = 12(240)

⇒ 6W = 240

⇒ W = 40

⇒ The Rate of Wind is 40 mi/h

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic