brainliest if 2 ppl answer : )

Problem 1

Answers: (-4,-12); (1,-2); (2,-18)

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The x coordinates of the relative min and max are x = -3 and x = 1/3 = 0.33 respectively. Any point that has an x coordinate between these two values will be on an increasing interval. Going from a relative min to a relative max means we go uphill. Anything outside this interval will be on a deceasing interval. The points outside this interval are (-4,-12) and (1,-2) and (2,-18)

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Problem 2

Answer that goes in the blank: 7

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Use the log rules

log(x)+log(y) = log(x*y)

log(x)-log(y) = log(x/y)

to get the following

log(14/3) + log(11/5) - log(22/15)

log((14/3)*(11/5)) - log(22/15)

log(154/15) - log(22/15)

log((154/15)/(22/15))

log((154/15)*(15/22))

log(154/22)

log(7)

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Problem 3

see the attached image below

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The rule is that log(b,x) = y turns into b^y = x, where b is the base of the log and exponent

So log(2,x) = 5 turns into x = 2^5 = 32. The same applies for the others as well.

Note: log(3,x) = 1 turns into x = 3^1 = 3, but x = 3 isn't listed as an answer

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,