Aswimming pool is being filled and begins ejth 400 gallons of water in it. after 8 minutes, the pool contains 816 gallons of water. assuming that water is being poured into the pool at a constant rate, how much water will it contain after a total of 20 minutes has passed?

y  = 52x + 400

Step-by-step explanation:

A linear model has the form y = mx + b

There are two variables: the volume (y) of water and the number (x) of minutes the pool has been filling. The volume of water depends on how long the pool is filling.

m = (y₂-y₁)/(x₂ -x₁)

x₁ = 0; y₁ = 400

x₂ = 8; y₂ = 816

m = (816 - 400)/(8 - 0)

m = 416/8

m = 52 gal/min

The initial value (b) is the volume at time zero.

b = 400 gal  

The linear function is

y = 52x + 400

Volume after 20 min

y = 52×20 + 400

y = 1040 + 400

y = 1440 gal

The pool will contain 1440 gal in 20 min.

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.