Mathematics, 29.06.2019 23:00 kiaramccurty
(algebra 2 conics): -1/4(y+2)^2 = x-7 i know this is a parabola, but i don't know how to find the vertex, focus, and directrix.
Answers: 1
![\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ 4p(y- k)=(x- h)^2 \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ -\cfrac{1}{4}(y+2)^2=x-7\implies -\cfrac{1}{4}[y-(-2)]^2=x-7 \\[2em] [y-(-2)]^2=-4(x-7)\implies [y-(\stackrel{k}{-2})]^2=4(\stackrel{p}{-1})(x-\stackrel{h}{7})](/tpl/images/0032/6819/659b8.png)
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(algebra 2 conics): -1/4(y+2)^2 = x-7 i know this is a parabola, but i don't know how to find the v...
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