Amerchant has coffee worth $60 a pound that she wishes to mix with 50 pounds of coffee worth $90 a pound to get a mixture that is worth $70 a pound. how many pounds (lb) of the $60 coffee should be used?

Step-by-step explanation:

Alright, lets gets started.

Suppose she mixes x pounds of coffee of $ 60 a pound.

So, the cost of that coffee =

Merchant has 50 pounds of coffee worth $ 90 a pound, hence the cost of this second coffee =

The mixture she get, is worth $ 70 and the weight of this mixture will be

So, the cost of mixture will be =

Addition of both coffees will be equal to the mixture, so

Subtracting 60 x in both sides

Subtracting 3500 in both sides

Dividing 10 in both sides

x = 100 pounds

It means she needs to add 100 pounds of that coffee.  :  Answer

Hope it will help :)

abde or 1,2,4, 5 is the answer

step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.