Mathematics, 05.11.2019 07:31 mely2668
For today’s lunch, a school cafeteria’s budget allows it to purchase at most 60 cans of beans and 45 cans of corn. 1 can of beans feeds 5 students, and 1 can of corn feeds 6 students. each student will have beans or corn, but not both, and there will be a maximum of 420 students at lunch. if a can of beans cost $2.00 and a can of corn cost $3.00, what is the maximum amount of money required to feed all of the students either beans or corn?
a: $180
b: $195
c: $210
d: $225
Answers: 1
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For today’s lunch, a school cafeteria’s budget allows it to purchase at most 60 cans of beans and 45...
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