Two jet planes simultaneously started traveling in opposite directions from the same airport. four hours later they were 3800 miles apart. find the rate of each plane, if one of them traveled 80 miles per hour faster than the other.

Rate of travelling of the 2 planes = 435 mph and 515 mph

Step-by-step explanation

d1 + d2 = 3800     (where d1 and d2 are the distances travelled by  each plane).

Let v1 = velocity of first plane so v1 + 80 will be velocity of the second)

They both travelled for 4 hours

Distance = time * speed.

So  d1 = 4v1  and  d2 = 4(v1 + 80)

Substituting for d1 and d2 in the first equation:-

4v1 + 4(v1 + 80) = 3800

8v1 + 320 = 3800

8v1 =  3480

v1 =  435 mph

and  v1 + 80 = 515 mph

a 10 percent increase

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10