Part a: mrs. konsdorf claims that angle r is a right angle. is mrs. konsdorf correct? explain your reasoning part b: if t is trabsformed under the rule (x, y) (x-1,y-2) then does t' form a right angle at < grt'?

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

The product of slopes of two perpendicular lines is -1.

Slope of GR is

Slope of RT is

Product of slopes of GR and RT is

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

Then the coordinates of T' are

Slope of RT' is

Product of slopes of GR and RT' is

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

they can either have 0,1, or infinite solutions

step-by-step explanation: