Find the area of a trapezoid with bases 12 cm and 18cm and height 10cm

150 cm^2 (squared)

Step-by-step explanation:

Area of a trapezoid is A=1/2(Base1 + Base2) x Height or

A= ((Base1 + Base2) / 2) x height

((12+18)/2) x 10

((30)/2) x 10

(15) x 10

150 cm^2

So in this case it would be 12+18 which is 30

((12+18)/2) x 10

((30)/2) x 10

Then 30 divided by 2 is 15.

(15) x 10

15 times 10(height) is 150.

Then add the units (cm) and squared since the area.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.