Write an equation in slope-intercept form of the line that passes through the point (8, 2) and is parallel to the graph of the equation y=4x-3

y = 4x - 30

Step-by-step explanation:

The general slope-intercept equation for a straight line is

y = mx + b

For y = 4x – 3, m = 4

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The other equation passes through (8,2) and has slope 4:

y = 4x +b     Set x = 8, y = 2.

2 = 4×8 + b

2 = 32 + b     Subtract 32 from each side

b= -30

The equation for the second graph is

y = 4x – 30

The graph below shows Equation (1) as a red line.

The graph of Equation 2 is the green line that passes through (8,2), runs parallel to Equation (1), and has a y-intercept at (0,-30.

sorry man i accidentally pressed yes my bad

step-by-step explanation: