During an evening out, dean paid a cab driver $20. he then spent $25 on dinner and half of his remaining money on a painting. he bought an umbrella for $23.75 and had $42.15 left. how much money did dean have at the beginning of the evening?

The way I see it is like this:

He ended with $42.15 -- the last thing that he did before that was buy the umbrella

$42.15 + $23.75 (umbrella) = $65.90

The next thing backwards in order is that he spent "half of his remaining money on a painting", so what he has left is one half what he had before he bought the painting.

$65.90 + $65.90 (cost of the painting) = $131.80

Before that, he spent $25 on dinner and $20 on a cab. So we add those all up:

$131.80 + $25 (dinner) + $20 (cab) = $176.80 (how much money he had at the start of the weekend)

To write it as a single equation:

$42.15 = -$23.75 + (-$25.00 + -$20.00)/2

110.90

Step-by-step explanation:

because 20.00+25.00+23.75=68.75+42.15=110.90

answer: the answer is ann

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0