In abc gf=17 in the what is the length of cf

CF = 51

Step-by-step explanation:

Given that ABC is a triangle. D,E, F are midpoints of BC, CA and AB respectively.

AD, BE and CF are the medians of the triangle.  The three medians concur at a point G.  G is the centroid of the triangle.

We know from triangle theorem that the centroid divides each median in the ratio 2:1

Here hence CG:GF = 2:1

Or CG+GF:GF = (2+1):1

So CF: GF = 3:1

Or CF = 3 GF

Since GF = 17 is given we get

CF = 3(17) = 51

step-by-step explanation:

i'm not sure how to show the work for this

answer : c and d or 4(29 + 6)

4(29) + 4(6)