Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. she has several pounds of a mixture that is 80% peanuts and 20% almonds and several pounds of a mixture that is 50% peanuts and 50% almonds. a. what is the system that models this situation? b. what is the solution to the system? how many pounds of the 80/20 mixture? how many pounds of the 50/50 mixture?

a.  The system of equations that models the situation is....

b.  The solution to the system:  x = 2 and y = 4

The amount of 80/20 mixture is 2 pounds and the amount of 50/50              mixture is 4 pounds.

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is   pounds and the amount of 50/50 mixture is   pounds.

So, the amount of peanuts in 80/20 mixture pound and the amount of almonds in 80/20 mixture pound.

And the amount of peanuts in 50/50 mixture pound and the amount of almonds in 50/50 mixture pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture pounds

and the amount of almonds in that mixture pounds.

So, the system of equations will be.........

Subtracting equation (2) from equation (1), we will get.....

Now, plugging this into equation (1), we will get......

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

step-by-step explanation:

4227473658779875563886538705958641728563470543621287463824132573847969p05749365273847906970680574936214