The length of a rectangle is 3 more than the width. find the length of the rectangle if the perimeter is 98 in

The length of the rectangle is 26 in

Step-by-step explanation:

Width of the rectangle: W

The length of the rectangle is 3 more than the width:

Length of the rectangle: L=3 in+W

Find the length of the rectangle if the perimeter is 98 in:

L=?

Perimeter: P=98 in

P = 2(L+W)

Replacing P by 98 in and L by 3 in+W in the equation above:

98 in = 2[(3 in+W)+W]

98 in = 2(3 in+W+W)

98 in = 2(3 in+2W)

Solving for W: Dividing both sides of the equation by 2:

98 in / 2 = 2(3 in+2W)/2

49 in = 3 in+2W

Subtracting 3 in both sides of the equation:

49 in - 3 in = 3 in +2W - 3 in

46 in = 2W

Dividing by 2 both sides of the equation:

46 in / 2 = 2W/2

23 in = W

W=23 in

Finally:

L=3 in +W

Replacing W by 23 in in the equation above:

L=3 in + 23 in

L=26 in

answer: l

step-by-step explanation:

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft