The test scores for 10 students in ms. sampson’s homeroom were 61, 67, 81, 83, 87, 88, 89, 90, 98, and 100. create a frequency table with the intervals 61-70, 71-80, 81-90, 91-100

The required frequency table,

Class Interval:     61 - 70          71 - 80            81 - 90          91 - 100

Frequency:            2                     0                      6                    2

Step-by-step explanation:

Here, test scores for 10 students are,

61, 67, 81, 83, 87, 88, 89, 90, 98, and 100.

Since, In interval  61 - 70, scores are 61 and 67.

Therefore, frequency of interval 61 - 70 = 2

In interval 71 - 80, there are no scores.

Therefore frequency of interval 71 - 80 = 0

In Interval 81 - 90, scores are , 81, 83, 87, 88, 89 and 90.

Therefore  frequency of interval 81 - 90 = 6

In Interval 91 - 100, scores are 98 and 100.

Therefore, frequency of interval 91 - 100 = 2

answer:

your answer is: c. 196 7/8 in^3.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.