Consider the following system of equations. 2x-y=12 -3x-5y=-5 the steps for solving the given system of equations are shown below. step one -5(2x-y=12) -3x-5y=-5 step two -10x+5y=-5 step 3 -13x=-65 step 4 x=5 step 5 2(5)-y=12 step 6 y=-2 solution (5,-2) select the correct statement about step 3. a. when the equations -10x + 5y = -60 and -3x − 5y = -5 are added together, a third linear equation, -13x = -65, is formed, and it has a different solution from the original equations. b. when the equation -3x − 5y = -5 is subtracted from -10x + 5y = -60, a third linear equation, -13x = -65, is formed, and it has a different solution from the original equations. c. when the equations -10x + 5y = -60 and -3x − 5y = -5 are added together, a third linear equation, -13x = -65, is formed, and it shares a common solution with the original equations. d. when the equation -3x − 5y = -5 is subtracted from -10x + 5y = -60, a third linear equation, -13x = -65, is formed, and it shares a common solution with the original equations. reset next