Where is the location of the vertex of the parabola on a coordinate grid? y=x^2+2x-3 above the x-axis below the x-axis on the x-asxis on the y-axis

below the x-axis

Step-by-step explanation:

y=x^2+2x-3

the vertex is located on the axis of symmetry

h

to find h      ax^2 +bx+c

h= -b/2a   = -2/2(1)  = -1

the x coordinate of the vertex is -1

to find the y coordinate, substitute into the equation

y = (-1)^2 +2(-1) -3

  = 1-2-3

   = -4

(-1,-4)

the vertex is below the x axis

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step-by-step explanation:

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x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17