1. an empty kitchen cabinet has 8 shelves, and each shelf can hold no more than 30 cans. you want to arrange 40 cans in the kitchen cabinet so that the same number of cans is on each shelf that you use. a.) list the factors of 40. b.) list the factors of 40 that represent the number of cans that could be on each shelf. c.) how many different arrangements of cans are possible? d.) what are the possible arrangements of the cans? e.) which arrangement uses all the shelves?

a.) list the factors of 40.

1/2/4/5/8/10/20/40

b.) list the factors of 40 that represent the number of cans that could be on each shelf.

5

c.) how many different arrangements of cans are possible?

just one because if you put more on one shelf you will go way over 40 and the cabinet will probably break.

d.) what are the possible arrangements of the cans?

put 5 cans on each self to reach 40 cans in total.

e.) which arrangement uses all the shelves?

5 because you can put 5 cans on each shelf, and since there are 8 shelfs you are equally going to get 40 cans.

step-by-step explanation:

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: