What is the vertex and axis of symmetry for y=4x^2-12x+9?

axis of symmetry   x=3/2

vertex  (3/2, 0)

Step-by-step explanation:

to find the axis of symmetry we use h = -b/2a

where ax^2 + bx+c

h = -(-12)/2(4)

h= 12/8

h = 3/2

the axis of symmetry is x = 3/2

the x coordinate of the vertex is h x=3/2

to find k, the y coordinate of the vertex, substitute x=3/2 into the equation

y=4x^2-12x+9

y=4(3/2) ^2-12(3/2)+9

 = 4 (9/4)  - 6*3 +9

  = 9-18+9

  = 0

the vertex (3/2, 0)

4

step-by-step explanation: