In parallelogram abcd , diagonals ac¯¯¯¯¯ and bd¯¯¯¯¯ intersect at point e, ae=x2−16 , and ce=6x . what is ac ? the answer is 96.

The answer is 96 when X= 8

Step-by-step explanation:

We have given that :

AE=  and CE=

where AE and CE are the diagonals of the paralleogram

The diagonals of parallelogram bisect each other therefore,

⇒

factors are (x+2)(x-8)=0

setting to each factor 0 the value of x= -2 or x= 8

therefore, two values of AC is

X= -2  ,AC= 2()=2(-12)=-24

X= 8 ,AC= 2()=2(48)=96

The answer is 96 when X= 8

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

step-by-step explanation:

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