Find the perimeter and area of a right triangle with legs of 24 feet and 41.57 feet and a hypotenuse of 48 feet

Perimeter≈113.57 and Area= A≈498.84

Step-by-step explanation:

Ok so the Perimeter is approximately 113.57. the formula of a perimeter of a right triangle is P=a+b+√a²+b²

so since a and b are the leg in the right riangle then the value we are gonna be working with are 24 and 41.57

so basically the equation states this: P=24+41.57+√24²+41.57²

so 24+41.57 is 65.57

24²=576 and 41.57²=1728.1(rounded) add that and you get 2304.1. the square root of 2304.1 is 48.00104166 or just 48. add that to 65.57 and you get 113.57

Now for area.

the area of right triangle is ab/2

so 24times 41.57 divided by 2

24 times 41.57= 997.68

divide that by 2 and you get 498.84

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1