Apolynomial function has a root of –3 with multiplicity 2, a root of 0 with multiplicity 1, a root of 1 with multiplicity 1, and a root of 3 with multiplicity 2. if the function has a positive leading coefficient and is of even degree, which could be the graph of the function?

The first graph picture

Step-by-step explanation:

A polynomials is an equation with many terms whose leading term is the highest exponent known as degree. The degree or exponent tells how many roots exist. These roots are the x-intercepts.

This polynomial has roots -3, 0, 1, and 3. This means the graph must touch or cross through the x-axis at these x-values. What determines if it crosses the x-axis or the simple touch it and bounce back? The even or odd multiplicity - how many times the root occurs.

In this polynomial:

Root -3 has even multiplicity of 2 so it only touches and does not cross through.

Root 0 has odd multiplicity of 1 so crosses through.

Root 1 has odd multiplicity of 1 so crosses through.

Root 3 has even multiplicity of 3 so it only touches and does not cross through.

Knowing this, only the first and second graphs are possible answers.

Lastly, what determines the facing of the graph (up or down) is the leading coefficient. If positive, the graph ends point up. If negative, the graph ends point down. All even degree graphs will have this shape.

Only graph 1 matches the features of this polynomial.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

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